Donate to us!
The important thing is not to stop questioning. - Albert Einstein
Sunday, December 17, 2017
Advertise on HBH
Submit an issue
Basic Web Hacking
Hall of Fame
Total Online: 70
Guests Online: 67
Members Online: 3
Registered Members: 103432
Introduction to Prog...
Complete Anonymity G...
PLC Electronic Basic...
Introduction to PLC...
Using Google Search ...
Pen testing 2 walk t...
Top 10 Simple Home S...
Pen Testing 2...
5 Firefox Addons Eve...
IT Security, a way o...
WIFI - Part 6, Airod...
WIFI - Part 6, Airod...
WIFI - Part 5, OSI a...
Create an account
Reset an account
Posted on 25-02-10 22:58
We're gong over subnetting in class and its really not clicking.
I understand we barrow bits from the host portion and put it on the network bits, but thats as far as I could understand.
Lets say i wanted two networks. One with 30 hosts and the other with 50.
Class C IP.
I believe i need to take two bits from the host side, making the new subnet 255.255.255.129?
and the first rang of IP's 192.168.1.0-192.168.1.64?
second range being 192.168.1.65-192.168.1.129?
Posted on 15-04-10 09:23
moshbat is right you should have your teacher explain.....here is the correct answers for your example if you were wondering
your two networks would be 192.168.1.0 - 192.168.1.63
and the second would be 192.168.1.64 - 192.168.1.127
subnet mask /26 or 255.255.255.192
so you have 192.168.1.xxxx xxxx x being the bits
the values of x is as follows 128, 64, 32, 16, 8, 4 , 2 , 1
and you need a max number of 50 hosts. So we will pick 64. 64 is able to hold 50 hosts plus a couple more....
your range of hosts is 64
and 0 counts so we get the networks
192.168.1.0 - 192.168.1.63
192.168.1.64 - 192.168.1.127
*+2 more networks if you want to work it out*
For the subnet mask.... since we used 64
we had to barrow 2 bits from the 4th octet
to find your subnet mask add those two bits you borrowed
so it would be 128+64 which = 192
so your subnet mask is 255.255.255.192
ehhh i hope this helped lol it may seem hard at first but once you understand it, it is fairly easy
Posted on 15-04-10 19:52
Thanks it does help, and it showed that I was right.
The teacher said it was an introduction, and that we will be going over it more in depth the third semester next year, along with VLAN.
Hellbound Hackers is the collective work of the staff and the community and is therefore licensed under the CC BY-NC-SA license.
© Hellbound Hackers 2003 - 2017
Terms of Service