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Thursday, April 24, 2014
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HellBound Hackers | Computer General | Networking

Author

Subnetting....

techb
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Posted on 25-02-10 22:58
We're gong over subnetting in class and its really not clicking.
I understand we barrow bits from the host portion and put it on the network bits, but thats as far as I could understand.

Lets say i wanted two networks. One with 30 hosts and the other with 50.
Class C IP.

I believe i need to take two bits from the host side, making the new subnet 255.255.255.129?

and the first rang of IP's 192.168.1.0-192.168.1.64?
second range being 192.168.1.65-192.168.1.129?




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RE: Subnetting....

ksarto
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Posted on 15-04-10 09:23
moshbat is right you should have your teacher explain.....here is the correct answers for your example if you were wondering


your two networks would be 192.168.1.0 - 192.168.1.63
and the second would be 192.168.1.64 - 192.168.1.127


subnet mask /26 or 255.255.255.192


so you have 192.168.1.xxxx xxxx x being the bits

the values of x is as follows 128, 64, 32, 16, 8, 4 , 2 , 1

and you need a max number of 50 hosts. So we will pick 64. 64 is able to hold 50 hosts plus a couple more....

your range of hosts is 64

and 0 counts so we get the networks

192.168.1.0 - 192.168.1.63
192.168.1.64 - 192.168.1.127

*+2 more networks if you want to work it out*


For the subnet mask.... since we used 64

we had to barrow 2 bits from the 4th octet

192.168.1.xx|xx xxxx

to find your subnet mask add those two bits you borrowed

so it would be 128+64 which = 192
so your subnet mask is 255.255.255.192


ehhh i hope this helped lol it may seem hard at first but once you understand it, it is fairly easy


Author

RE: Subnetting....

techb
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Posts: 384
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Posted on 15-04-10 19:52
Thanks it does help, and it showed that I was right.

The teacher said it was an introduction, and that we will be going over it more in depth the third semester next year, along with VLAN.



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