| Author | Steg25 |
jmort47
Member
Posts: 22
Location:
Joined: 27.05.13
Rank: God | |
| Alright. I've found the "answer" but its obviously encoded in a clever way. I know what "encryption" it isn't, because I've tried several different encryptions. Normally I can logic this stuff out, but I'm completely stumped on this one. A nudge would be great. |
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| Author | RE: Steg25 |
Ninja
Member
Posts: 14
Location: 1337
Joined: 02.05.13
Rank: God | |
Yeah I have the same problem I find an answer but no idea how to decrypt. Tried many things.
http://caimeo.co.nf |
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| Author | RE: Steg25 |
Euforia33
philalethes
Posts: 881
Location:
Joined: 05.10.09
Rank: God | |
| PM me what you have so far. |
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| Author | RE: RE: Steg25 |
Akula
Member
Posts: 6
Location: root
Joined: 27.01.13
Rank: God | |
Hopefully, this will not spoil the challenge for anyone.
Possibly confuse some people *hmm*
I have solved the stego part of this challenge, which I really enjoyed. First I did it partly, and could not make sense of it. And then I dug some more and unvealed the hidden secret.
But understanding the secret maybe belongs to encryption challenges?
I cannot unriddle this.. I have tried morse code, gray code and multiple character encodings. Part of the problem is that it is not obvious which direction to read the bits. I have tried forward, backward, up, down, group by four, by eight and so on.
Problem with character encoding, is that there are probably more encoding schemes than there are encryption algorithms. So the problem is finding the algorithm, not the key. A small collection of bits with no encoding information really makes no sense. I could decrypt this with a 64 bit XOR key and get whatever result I want, but of course not the correct answer.
Maybe I just did not guess an obvious encoding. What would really help is to know how many bits create a character. Is it 4, 8, 16?
Also, which is zero and which is one?
To make it clear, I have these possibilities for the first 4 bits of the secret:
0110 0111 0101 1001 1000 1010
These are following natural directions starting from the top left without knowing which is zero and which is one.
If I grey decode them, I get these options:
0100 0101 0110 1110 1111 1100
Maybe I'm just being stupid, or lazy.
I think it is rather easy to create an 'unbreakable' crypto if you are only encrypting a small amount of characters. E.g. OTP is actually unbreakable as long as the key is secret.
Edited by Mordak on 17-07-13 04:06 |
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| Author | RE: Steg25 |
Dark executer
Member
Posts: 4
Location: India
Joined: 20.10.12
Rank: God | |
| hey is it a random password or a meaning full one?? |
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| Author | RE: Steg25 |
rex_mundi
☆ Lucifer ☆
Posts: 2017
Location: Scotland
Joined: 20.02.08
Rank: God | |
| It's not random no. |
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| Author | RE: Steg25 |
psyl0cke
Member
Posts: 824
Location: sharing love everywhere ♥
Joined: 01.07.13
Rank: God | |
When you catch the right answer you will know it when you look at it.  |
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| Author | RE: Steg25 |
Dark executer
Member
Posts: 4
Location: India
Joined: 20.10.12
Rank: God | |
| thanks rex and psyl0cke |
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| Author | RE: Steg25 |
Akula
Member
Posts: 6
Location: root
Joined: 27.01.13
Rank: God | |
Yeah, it's normally like that, psyl0cke When you first see it, you know you're on the right track. But before that, you just bang your head against the wall  |
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| Author | RE: Steg25 |
jmort47
Member
Posts: 22
Location:
Joined: 27.05.13
Rank: God | |
I'm still stuck on this stupid thing. I know exactly what to do to find the answer, but none of the combinations are workin. I'm still getting a bunch of gibberish.
*punches Euforia with my brain*
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| Author | RE: Steg25 |
Euforia33
philalethes
Posts: 881
Location:
Joined: 05.10.09
Rank: God | |
Vi veri universum vivus vici. |
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| Author | RE: Steg25 |
Akula
Member
Posts: 6
Location: root
Joined: 27.01.13
Rank: God | |
Finally I got it.
Jeez!
Thank you rex, for usefull hints 
Now this challenge is all about permutations.
I actually solved it using a known plaintext attack
I will give you all a hint:
Normally, we tend to start at the beginning when decoding stuff.
But, try to think of an encoding that has a magic byte in the end, not the beginning. Then looking for this byte in the end should reveal the permutation scheme.
However, you are still not finished. PM me if you are still banging your head. Remember, I said this challenge is all about permutations... |
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