You must show your work in binary when you make these calculations. You cannot just run this through a compiler. I mean you can (lol), but it defeats the purpose of the exercise, as you need to understand what's going on in the background. I will post my solution later.
List the output:
int main(int argc, char ** argv){
int x = 0x23;
int y = 0x15;
x = x << 16;
printf(“%x\n”, x);
x = (x | y) << 8;
printf (“%x\n”,x);
printf (“%x\n”, y);
x = 0x12345678;
y = 0x55;
x = ((x<<8) & (y<<8))>>8;
printf(“%x\n”, x);
x = 0x23;
y = 0x15;
x = x ^ y;
printf(“%d\n”, x);
x = y ^ x;
printf (“%d\n”,x);
y = y ^ x;
printf (“%d\n”, y);
