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Timed 4 |
The_Gman
Member
Posts: 30
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Rank: Mad User |
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Honestly I have no idea what they mean with their rules. Do they mean swap the characters, add to the ascii values, or do they mean make a new string selecting the odd characters plus the second?
Thanks, |
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RE: Timed 4 |
ynori7
Future Emperor of Earth
Posts: 1481
Location: #valhalla
Joined: 08.10.07
Rank: Diabolical |
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They gave you pseudo code. If you can't understand that then you aren't ready for this challenge.
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RE: Timed 4 |
The_Gman
Member
Posts: 30
Location:
Joined: 02.09.08
Rank: Mad User |
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final += final[i]?
I understand pseudo code, but that isn't correct, unless they mean append or something, and I don't want to waste my time. |
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RE: Timed 4 |
ynori7
Future Emperor of Earth
Posts: 1481
Location: #valhalla
Joined: 08.10.07
Rank: Diabolical |
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Think of final as an empty string, and you just add characters to it in the right spot as you get to them while you trace through your scrambled string.
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RE: Timed 4 |
jjbutler88
Colemak User
Posts: 590
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Rank: Guru |
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The_Gman wrote:
final += final[i]?
I understand pseudo code, but that isn't correct, unless they mean append or something, and I don't want to waste my time.
You code python, thats valid code for appending to a string.
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RE: Timed 4 |
Mouzi
Member
Posts: 144
Location: Finland
Joined: 08.08.06
Rank: God |
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The_Gman wrote:
final += final[i]?
I understand pseudo code, but that isn't correct, unless they mean append or something, and I don't want to waste my time.
IMO you're right. There is actually an error in the pseudo code.
FOR i = 0; i < str.length; i++
IF isEvenOrZero(i)
final += final[i]
ELSE
final += final[i+2]
END FOR
final += final[1]
RETURN final
In the line where it says final += final[i] the final[i] would be null, because the final is a nonexistent variable at this point. It should actually say final += str[i], because str is the variable referred to on the first line. I believe str in this case refers to the string given in the challenge. Same goes for the next ones too (final[i+2] and final[1]). On the last line the final variable would still be null.
Steganographs
Edited by Mouzi on 14-09-08 12:11 |
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RE: Timed 4 |
The_Gman
Member
Posts: 30
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Joined: 02.09.08
Rank: Mad User |
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That makes a lot more sense.. I'll post in ten minutes with [hopefully] my success  |
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RE: Timed 4 |
The_Gman
Member
Posts: 30
Location:
Joined: 02.09.08
Rank: Mad User |
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wait wait, what about the last odd character? str[i+2] clearly won't work.
And we're trying to REVERSE that algorithm, correct?
something like this? (although this won't run)
code = 'x'*len(word)
code[1] = word[len(word)-1]
for i in range (len(word)):
if (i%2 == 0):
code[i] = word[i]
else:
code[i+2] = word[i]
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